Parse a YAML file in Python

This post will discuss how to parse a YAML file in Python.

1. Using `yaml.load()` function

The PyYAML module is a recommended YAML parser and emitter for Python. To convert a YAML file to a Python object, you can use the yaml.load() function.

If your YAML data is coming from trusted sources, you can specify the Loader=FullLoader argument, which loads the full YAML language and avoid arbitrary code execution.

import yaml

with open('config.yaml') as f:

try:

dict = yaml.load(f, Loader=yaml.FullLoader)

print(dict)

except yaml.YAMLError as e:

print(e)

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This is equivalent to calling the yaml.full_load() function.

import yaml

with open('config.yaml') as f:

try:

dict = yaml.full_load(f)

print(dict)

except yaml.YAMLError as e:

print(e)

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2. Using `yaml.safe_load()` function

You can use the yaml.load() function to load the untrusted data, but only with yaml.SafeLoader Loader.

import yaml

with open('config.yaml') as f:

try:

dict = yaml.load(f, Loader=yaml.SafeLoader)

print(dict)

except yaml.YAMLError as e:

print(e)

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Alternatively, PyYAML provides a safe_load() function that can be used to load data by an untrusted source.

import yaml

with open('config.yaml') as f:

try:

dict = yaml.safe_load(f)

print(dict)

except yaml.YAMLError as e:

print(e)

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That’s all about parsing a YAML file in Python.

Parse a YAML file in Python

1. Using yaml.load() function

2. Using yaml.safe_load() function

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1. Using `yaml.load()` function

2. Using `yaml.safe_load()` function