Check whether a variable is an integer or not in Python

This post will discuss how to check whether a variable is an integer or not in Python.

1. Using `isinstance()` function

The standard solution to check if a given variable is an integer or not is using the isinstance() function. It returns True if the first argument is an instance of the second argument.

if __name__ == '__main__':

x = 10

isInt = isinstance(x, int)

print(isInt) # True

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You can also use numeric abstract base classes instead of concrete classes. To check for an integer value, you can use the numbers.Integral Python class:

import numbers

if __name__ == '__main__':

x = 10

isInt = isinstance(x, numbers.Integral)

print(isInt) # True

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2. Using `float.is_integer()` function

If you need to consider floats with all zeros after the decimal point, consider using the float.is_integer() function. It returns True if the float instance is finite with integral value and False otherwise.

if __name__ == '__main__':

x = 10.0

isInt = float(x).is_integer()

print(isInt) # True

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3. Using `int()` function

Finally, you can use the int constructor to check for integral values. The function int(x) converts the argument x to an integer. If x is already an integer or a float with integral value, then the expression int(x) == x will hold true.

if __name__ == '__main__':

x = 10.0

isInt = int(x) == x

print(isInt) # True

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That’s all about determining whether a variable is an integer or not in Python.

Check whether a variable is an integer or not in Python

1. Using isinstance() function

2. Using float.is_integer() function

3. Using int() function

Share this:

1. Using `isinstance()` function

2. Using `float.is_integer()` function

3. Using `int()` function