Convert a comma-separated string to a list in Kotlin

This article explores different ways to convert a comma-separated string to a list in Kotlin.

The standard way to split a Kotlin string is with the split() function. We can use the split() function to convert the comma-separated string to a list in the following ways:

1. Using `listOf()` function

The idea is to split the string with the split() function and pass the resultant array to the listOf function to get a new list.

fun main() {

val str = "A,B,C,D"

val list: List<String> = listOf(*str.split(",").toTypedArray())

println(list) // [A, B, C, D]

}

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2. Using `toList()` function

Another good solution is to directly call the toList() function after splitting the array with the split() function.

fun main() {

val str = "A,B,C,D"

val list: List<String> = str.split(",").toList()

println(list) // [A, B, C, D]

}

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3. Using `Pattern.compile()` function

Finally, you can split the string using the split() function around the matches of a pattern. This would translate to a simple code below:

import java.util.regex.Pattern

fun main() {

val str = "A,B,C,D"

val list: List<String> = Pattern.compile(",").split(str).toList()

println(list) // [A, B, C, D]

}

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That’s all about converting a comma-separated string to a list in Kotlin.

Convert a comma-separated string to a list in Kotlin

1. Using listOf() function

2. Using toList() function

3. Using Pattern.compile() function

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1. Using `listOf()` function

2. Using `toList()` function

3. Using `Pattern.compile()` function