## Find maximum width of given binary tree

Given a binary tree, write an efficient algorithm to compute maximum width of it.

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Binary Trees

Given a binary tree, write an efficient algorithm to compute maximum width of it.

Given an array A which represents a binary tree such that the parent-child relationship is defined by (A[i], i) for every index i in the array A, build binary tree out of it.

Given a binary tree, write an efficient algorithm to invert binary tree.

Given a normal binary tree, convert it to Left-child right-sibling (LC-RS) binary tree.

Huffman Coding (also known as Huffman Encoding) is a algorithm for doing data compression and it forms the basic idea behind file compression. This post talks about fixed length and variable length encoding, uniquely decodable codes, prefix rules and construction of Huffman Tree.

Given a binary tree, write an efficient algorithm to check if tree is height balanced or not. In a height balanced tree, the absolute difference between height of left subtree and right subtree for every node is 0 or 1.

Given a binary tree, write an efficient algorithm to print binary tree structure in standard output.

Given a binary tree, calculate sum of all nodes for each diagonal having negative slope (\). Assume that the left and right child of a node makes 45 degree angle with the parent.

Given a Binary Tree, determine if it is a BST or not. This problem has a simple recursive solution. The BST property “every node on the right subtree has to be larger than the current node and every node on the left subtree has to be smaller than the current node” is the key …

Given a binary tree, write an efficient algorithm to find maximum sum root to leaf path i.e. maximum sum path from root node to any leaf node in it.

Given a binary tree, a complete path is defined as a path from root to a leaf. The sum of all nodes on that path is defined as the sum of that path. Given a number K, remove nodes from the tree which lie on a path having sum less than K.

Given a binary tree, convert it to full tree by removing half nodes (remove nodes having one children).