## Reverse linked list | Part 2 (Recursive Solution)

Given a singly list it, reverse it using recursion.

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Given a singly list it, reverse it using recursion.

Given a singly linked list it, reverse it.

Given two lists sorted in increasing order, create and return a new list representing the intersection of the two lists. The new list should be made with its own memory — the original lists should not be changed.

Given a linked list, sort it using merge sort algorithm. Merge sort is an efficient, general-purpose sorting algorithm which produces a stable sort, which means that the implementation preserves the input order of equal elements in the sorted output. Mergesort is a comparison sort, i.e. it can sort items of any type for …

Write a function that takes two lists, each of which is sorted in increasing order, and merges the two together into one list which is in increasing order and return it.

Given two linked lists, merge their nodes together to make one list, taking nodes alternately between the two lists. If either list runs out, all the nodes should be taken from the other list.

Given a linked list, split its into two lists where each list containing alternating elements from the original list. The elements in the new lists may be in any order.

Rearrange the given linked list such that every even node will be moved to end of the list in reverse order.

Given a linked list, move front node of it to the front of the another given list.

Given a linked list sorted in increasing order, write a function which removes any duplicate nodes from the list by traversing the list only once.

Given a list, split it into two sublists — one for the front half, and one for the back half. If the number of elements is odd, the extra element should go in the front list.

Given a linked list, write a function to rearrange its nodes so they are sorted in increasing order. In other words, sort linked list.